Question

please help solve all 3 problems! show your work on how you got to ur answer. thank you

1. A student has a cell suspension of 10 cells/ml. How is he going to prepare 10 ml of a 10 cells/ml suspension? (1 point) 2. A student has a cell suspension of 3.2 x 10' cells/ml. How is she going to prepare 10 mls of a 10 cells/ml suspension? (1 point) 3. A student has a cell suspension of 3 x 10' cells/ml. How is she going to prepare 5 mls of a culture at the concentration of 1000 cells/ml? (1 point)

Answer 1

12 inital 22 final Answer. For dilution! - mivia MzU2 o mia 105cens vir 9 L M22 103 ceny za 10mL los cels xv, = 103 cells x 10mL va 103 celux x10mL los celle = 0.1 mL so a student will take OlmL of solution, and dilute it 10mL r los ceux (mL

Now mi = 3.2x106 cells M₂ = 103 cens ir V, M₂u2 u = 9 V2 = 10ml mi So student solution Now = 10b elus XlomL 3.2x106ceus V = 3.125 x 10-3 mL swould take 3. 125 x 10-3amL of 3.2x106cang/mL and dilute it to some mi= 3x10s cells = 7 m2 = 103 cells u225 ml . U2 m₂ U2 mi - 103 cely x SmL 3x10 s cells - 1.67410-2ML should take 1.67X102mL of 3xlos celesful dilute it to SmL So slucent Seluton and