Question

L. 35. none of these choices is CUITCCL The following reaction is at equilibrium at a pressure of l atm, in a closed container. NaOH(s) + CO2(g) + NaHCO3(s): AHºrn <0 Which, if any, of the following actions will decrease the concentration of CO2 gas present at equilibrium? adding N2 gas to double the pressure adding more solid NaOH increasing the volume of the container lowering the temperature none of these choices is correct B.

Answer 1

According to le chatlier principle when any change in the equilibrium is done system tries to minimise the change by adjusting itself in such way.

Like addition of reactant shift reaction towards the product ​​​​​​

Ans B adding bore solid NaOH as addition of reactant will shift equilibrium toward product side so concentration of CO2 is decreased

Where addition of inert gas like CO2 will give no effect

Increasing the volume of container will decrease pressure of CO2 so more CO2 will be produced

As delta H is negtive so decrease on temperature also shift reaction towards product side.

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