P(failure of generator) =1-e-0.001*365*24 =0.999843
P(failure of electric system) =1-e-0.00023*365*24 =0.866653
electric power reliability of the year =1-P(both electric service and standby generator fails) =1-0.999843*0.866653
=0.133
option A is correct
the answer is 0.173... but how do I get it? The local telephone company has a...
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