pH ammonium
1. I have a beaker with 250.0 mL of distilled water. I dissolve 10.0 g of ammonium chloride (NH4Cl) and 10.0 g of methylammonium Chloride (CH3NH3Cl). What is the pH of the resulting solution?
Homework Answers
pH=pKa + log(b/a)
b=10/53.491
a=10/111.969
pH=5.11+ log(0.18/0.089)=5.43
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