Question

The scater diagram was predicted from the midterm score using regression line. Use the above information to question #2-1 to question #2-5: football-shaped For cach studen, the Final score was answer 2-13. (1 mark) Predict the final score for a student whose midierm score was unknown. C) 50 (D)60. A) 15 B) 20 2-14. (1 mark) Predict the midterm score for a sudent whose final score was 30. A)12 B)35 C43D) 51 None of the above. 2-15. (1mark) The above prpdiction is likely to be off by A)6 B)9 C) 10 DN2. points or so. 2-16. (1 mark) of the students who scored 70 on the midterm, about what percentage of students score above 88 on the final? A)16% B) 38% C)50% D) 68% E) 95 % 2-17. T mark) A deck of cards is shuffled. What is the chance that- The top card is not the jack of clubs and the bottom card is not the jack of clubs. A) (1/52) (1/51) F) 99.7% 2-11. (1 mark) Roll the tetrahedro B) 13.5 D) 33.5 )22.6 AD2 2-12. (1 mark) Roil the tetrahedron die 100 times. P[238s YS 300] is A) batween 0 and 0.20 B) between 0.20 and 0.40 C) betwoen 0.40 and 0.60 D) between 0.60and 0.80 E) between 0.80 and 1 Use the following information to answer the following questions (2-13 to 2-16 A research was made of the midterm and final scores in a targe course, with the following results: verage midterm score 60, SD- 10X average final score-60, SD-20, r-0.80 1.67-26 Y NeWAE I12-6 The scatter diagram was football-shaped. For each studenst, the Final score was predicted from the midierm score using regression line. Use the above informmation ta answer question #2-1 to question #2-5: for a student whose midherm score was 2-13. (1 mark) Predict the final score unknown A) 15 B) 20 C)50 (D)60. 2-14. (I mark) Predict the midternm score for a student whose final score was 30. A)12 B)35 C)430) 51 None of the above. 2-15. (I mark) The above prpdiction is likely to be off by A)6 B)9 C) 10 DN2 points or so -16. (1 mark) Of the students who scored 70 on the midterm, about what percent of students score above 88 on the final? (A)16% B) 38 % 950 % D)68 % E) 95 % F ) 99.7% 17. mark) A deck of cards is shuffled. What is the chance that- The top can t the jack of clubs and the bottom card is not the jack of clubs. A)(1/52) (1/5) B)(1/51) (51/52) C [1H1/521|1/51n 9570 h

Answer 1

Let X = mid-term score, Y = final score

2-13. As the mid-term score was unknown the predicted final score would be the average final score i.e. = 60 (D)

2-14 X_predicted = a + b y, where b= r(S_x / S_y) = 0.8 * (10/20) = 0.4 and a = avg (x) - b*avg (y) = 60 - 0.4 * 60 = 36

So, X_predicted = 36 + 0.4 (30) = 48 (None of the above) (D)

2-15 The above prediction is likely to be off by 60-48 = 12 (D)