a)
A molecule with N atoms has 3N degree of freedoms. Hence, since our molecule(SO2) has 3 atoms, the total number of degrees of freedom is 9.
b)
SO2 is a non-linear molecule. Hence, it has 3 translational and 3 rotational degrees of freedom. The remaining must be vibrational degrees of freedom.
Hence, the number of vibrational degrees of freedom in SO2 is
.
Hence, the answer is 3.
c)
E represents the identity operation. Hence, when we apply E on SO2, both the bonds remain unchanged. Hence, we put 2 in the table below E.
When we do a , through z axis, i.e
rotate the molecule by 180 degrees through z axis, we exchange the
positions of the S-O bonds. Hence, both the bonds are changed.
Hence, we put 0 under
.
When we put a reflection plane in the xz molecular plane, the
plane cuts all the three atoms in half. Hence, the bonds stay
unchanged. Hence, we put 2 under
operation.
When we put a reflection plane in the yz plane, it cuts the S
atom in half and exchanges the position of the O atoms. Hence, the
S-O bonds are exchanged in the process too. Hence, we put 0 under
operation.
Hence, the character table with the reducible representation is:
d)
The character table of point group
is
1 | 1 | 1 | 1 | |
1 | 1 | -1 | -1 | |
1 | -1 | 1 | -1 | |
1 | -1 | -1 | 1 |
Now, the reducible representation we found in part c) is
Lets find out how many times the irreducible representation
occurs in our
The formula to find this is
Where h is the order of the group = 4 for C2v point group as it has 4 unique operations.
is the character
of the reducible representation, i.e 2, 0 , 2 and 0 for
our reducible representations.
is the character
of the irreducible representation, i.e. for the first one, we are
finding for
, hence, the
characters are 1, 1, 1 and 1 (look at the character table for the
row A1.)
N is the number of symmetry operations in the particular class of operations.
hence, the number of times A1 occurs in our reducible representation is
Hence, the irreducible rerpesentation A1 occurs only 1 time in our reducible representation.
Similarly, the number of times A2 occur in our reducible representation is
Hence, A2 does not appear in our reducible representation.
The number of times B1 appear is
hence, B1 appears one time in the reducible representation.
The number of times B2 appear is
Hence, B2 does not appear in our reducible representation.
Hence,the reducible representation can be written as
Note that the basis we took to calculate the reducible representation are the S-O bonds, Hence, the reducible representation actually represent the vibration of the S-O bonds in SO2.
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