matlab code:
clc;clear all;
V1=100;R1=5000;
R2=100000;R3=200000;
R4=150000;
R5=250000;
i1=0.001; %assumed current
%V4 is voltage across R4
V4=V1-(i1*R1)
i4=V4/R4
i2=i1-i4
%V5is the voltage across R5
V5=V4-(i2*R2)
i5=V5/R5
i3=i2-i5
%V2 second source voltage
V2=V5-(i3*R3)
output:
V4 =
95
i4 =
6.3333e-04
i2 =
3.6667e-04
V5 =
58.3333
i5 =
2.3333e-04
i3 =
1.3333e-04
V2 =
31.6667
the possible range for V2=31.667 to 100 V
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