Question

VpD vo Rs

This is a very important assignment of mine please do it correctly I will give you thumbs up

Problem 1. The transistor in the circuit shown to the right has parameters V_TN = 0.4 V, K_n = = 0.5 mA / V², and λ = 0. The circuit parameters are V_DD = 3 V and R_i = R1||R2 = 300 kΩ.

a)Determine the values of R₁, R₂, and R_S such that I_DQ = 0.25 mA and V_DSQ = 1.5 V.

b)Determine the small-signal voltage gain

c) Determine the output resistance R_o

Answer 1

Given v_TN = 0.4 v k_n = k_n' w/L = 0.5 mA/v^2 lambda = 0 v_DD = 3 v and R_1 = R_1 Vertical-bar \R_2 = 300k Ohm Apply DC analysis given circuit 2) make capacitor circuit Given I_DQ = 0.25 mA and v_DSQ = 1.5 v apply kvl outside of the loop 3 = v_DSQ + IDQ R_s 3 = 1.5 + I_DQ R_s R_s = 1.5/I_DQ = 1.5/0.25 m = 6 k Ohm \r\n Apply equivalent at the input side we need to find the v_GS first we know that I_DQ 1/2 k_n' w/L (v_GS - v_TN)^2 0.25 m = 1/2 (0.5) (v_GS - 0.4)^2 v_GS = 1.4 v Apply kvl on the loop (1) 3 R_2/R_1 + R_2 = 1.4 + I_DQ R_s \r\n 3 R_2/R_1 + R_2 = 14 + 1.5 = 2.9 [given R_1 R_2/R_1 + R_2 = 300 k rightarrow R_1 + R_2 = R_1 R_2/300 k] 3 R_2/R_1 R_2 times 300 k = 2.9 R_1 = 900 k/2.9 = 310.24 k Ohm