Question

Please Explain to me in details how to plot and find the phase shift of any bode plot or any transfer function, I can't get it from the textbook! so please provide me a full explanation and solving of this example that will let me understand and solve any question like these!

Thumps up for any explanation in details & good font answer! otherwise thumbs down! :)

GOOD FONT ANSWER PLEASE!!

Phase Asymptotic approximation 90° Cs Rs ww V 450 Rp Actual curve f (log scale) 10 f= f= 2'S Figure 7.2 Series coupling capacitor circuit Figure 7.7 Bode plot of the voltage transfer function phase for the circuit in Figure 7.2 ww VDD=9 V VCC= 12 V RD Rc= k R1 10 k Rin Cc Rs 0.5 k ww Cc 0.1F R2 15 k R7 Rs= 0.5 k2 RE= 0.1 k Figure P7.18 Figure P7.17 D7.18 (a) Design the circuit shown in Figure P7.18 such that Ipo 0.8 mA VDSQ 3.2 V, Rin = 160ks2, and fi = 16 Hz. The transistor parameters are Kn 0.5 mA/V2, VTN = 1.2 V, and a = 0. (b) What is the midband volt age gain? (c) Determine the magnitude of the voltage gain at (i) f 5 Hz (ii)f 14 Hz, and (iii)f 25 Hz. (d) Sketch the Bode plot of the voltage gain magnitude and phase ww ww ww ww

Answer 1

Solution:

From the figure,

Apply KVL for the drain and source loop,

and Drain current equation of MOSFET, yields

7.18 (a) VDse VpDIg (RD R) 3.2 9-(0.8 RD +0.5)= Rp 6.75 k2 - - ID KVGsVIN) 0.8 0.5VGso1.2 VGso 2.465 V VG=(0.8 0.5)+2.465 2.865 V 71 so - (160)9) =R V 2.865 = VG DD in and R, = 235 kQ which yields R, = 503 k = 2/K,ID0 = 2/(0.5)0.8) =1.265 mA/V -(1.265 6.75 1+(1.265 0.5) (b) gm 8mRD =-5.23 Ay 1+gmRs 1 1 1 C 0.06217 uF > CC 2TRin CC (c) fL 27fR 27(1660x103 Ts R Cc (160x103 Y0.06217x10)=9.947x103s in in

The gain is calculated as, from the below equation,

f fi STS T. Ap 5.23 (5.23 1+sTs 2 f 1 + ft (i) For f 5 Hz 5 16 4 =(5.23) =1.56 2 5 16 (ii) For f 14 Hz 14 16 A (5.23 = 3.44 2 14 1 + 16

(iii) For f 25 Hz 25 16 4,=(5.23) - 4.405 2 25 + 16

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