Question

3 ft 1 ft 3 ft 1 ft A 1 ft 3 ft 12 3 3 For the two "organisms" shown above, calculate: 1) How much heavier is organism B than organism A? 2) How much stronger is the leg bone of organism B than that of organism A? 3) How thick would B's leg bone have to be in order for it to support B's weight as well as A's leg bone supports A's weight?

Answer 1

Answer 1:-

This can be calculated by means of calculating the dimensional weight. Its given as:-

DIMENSIONAL WEIGHT = Length × Breadth × Height/166 (standard measure for weight analysis on the basis of dimensional) We have to convert feet to inches (1 foot =12 inches)

Animal A=

1) Upper part =12 × 12 ×12 /166 = 10.40 lbs

2) Legs = 48 × 12 × 12 /166 × 4 = 166.55 lbs

Total weight = 294.03 lbs which equals to 133.36 kgs.

Animal B=

1) Upper part = 36 × 36 × 36/166 = 281.06 lbs

2) Legs = 144 × 36 × 36/166 × 4 = 4496.96 lbs

Total weight = 4778.02 lbs which equals to 2167.27 kgs.

Taking into consideration only Upper body weight, in animal A:-

1) Upper body weight is 281.06 lbs that equals to 127.48 kgs.

In animal B:-

2) Upper body weight is 10.40 lbs which equals to 4.71 kgs.

So, difference in body weight is (127.48 - 4.71 = 122.77 kgs). So, animal B is heavier than animal A by 122.7 kgs.