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HW 3-1 6-9 The beam shown in Fig. P6-9 supports the unfactored D 1.4 kips/f L...
The T-beam shown in Figure 1 supports the un-factored dead load of 1.4 kips/ft and live...
The T-beam shown in Figure 1 supports the un-factored dead load
of 1.4 kips/ft and live load of 1.5 kips/ft. The dead load does not
include the self-weight of the beam. The material properties are as
follows: fc’=3000 psi; fy=60,000 psi. Design the shear
reinforcement (stirrups). Plot the stirrups distribution along the
span of the beam.
DL= 1.4 kips/ft ; L2=1.5 kips/Ft * 75 Sz=7 X * b=3616. hr-6in k ) انا امه hw-lain + * bw=12 in
COURSE CE 3202 - Design of Concrete Structures SUBJECT HOMEWORK 4 DATE LECTURE # HW 4-2...
COURSE CE 3202 - Design of Concrete Structures SUBJECT HOMEWORK 4 DATE LECTURE # HW 4-2 A simply supported beam with the cross section shown in Fig. P9-5 has a span of 25 ft and supports an unfactored dead load of 1.5 kips/ft, including its own self-weight plus an unfactored live load of 1.5 kips/ft. The concrete strength is 4500 psi. Compute (a) the immediate dead load deflection. (b) the immediate dead-plus-live-load deflection. 16 No. 8 bars Fig. P9-5
Consider the beam subjected to a concentrated load consisting of 2.25 kips of dead load and...
Consider the beam subjected to a concentrated load consisting of
2.25 kips of dead load and 5.55 kips of live load at point B. Find
maximum factored beam shear, moment, and deflection.
Consider the beam and loading given below. The beam is subjected to a concentrated load consisting of 2.25 kips of dead load and 5.55 kips of live load at point B. Neglect beam weight. You may use any information from the AISC Manual, a) Draw the general shape...
4) A 100 foot long simply-supported bridge girder supports the unfactored loads shown in the figure....
4) A 100 foot long simply-supported bridge girder supports the unfactored loads shown in the figure. The uniformly distributed dead load, wD, includes the self weight of the girder, and is constant along the full beam length. Concentrated live loads, PL, are applied as shown in the figure. a) Draw factored shear force and factored bending moment diagrams in the spaces provided. Show magnitudes at locations A, B, C, D and E on each diagram.(8) PL = 50k PL-50k WD-2.5...
Figure 2 shows a simply supported beam and the cross section at mid span. The beam...
Figure 2 shows a simply supported beam and the cross section at mid span. The beam supports a uniform service (unfactored) dead load consisting of its own weight plus 1.4 kips/ft and a uniform service (unfactored) live load of 1.5 kips/ft. The concrete strength is 3500 psi, and the yield strength of the reinforcement is 60,000 psi. The concrete is normal-weight concrete. For the midspan section shown in Figure 2, compute фМп and show that it exceeds Mu. WD 1.4...
1. A rectangular beam with b 16 in., d-17 in., and h 20 in. has a clear span of 24 ft. as shown b...
1. A rectangular beam with b 16 in., d-17 in., and h 20 in. has a clear span of 24 ft. as shown below. The beam has 1 ft. of bearing at each end, so for analysis purposes it is treated as a 25 ft. simple span (to center of bearing at each end). The beam supports an unfactored concentrated live load of P-65 kips. The beam is reinforced with 6-#10 longitudinal bars and #4 stirrups. Material strengths are fc-4,000,...
Please answer question 1 thank you Reinforced Concrete HW 18%20(2).pdf CEE433- Homework Assignment 9 Assigned: 12...
Please answer question 1 thank you
Reinforced Concrete HW
18%20(2).pdf CEE433- Homework Assignment 9 Assigned: 12 April 2018 Due: 19 April 2018 1. Design the shear reinforcement (vertical stirrups) for the beam shown in the figure. Design stirrups based on the shear envelope using the approximate procedure discussed in class. Note that for the overhangs the maximum shear at the support is induced by placing dead and live loads throughout the cantilever portion. Satisfy all strength and spacing requirements specified...
Please answer question 1 thank you Reinforced Concrete HW 18%20(2).pdf CEE433- Homework Assignment 9 Assigned: 12...
Please answer question 1 thank you
Reinforced Concrete HW
18%20(2).pdf CEE433- Homework Assignment 9 Assigned: 12 April 2018 Due: 19 April 2018 1. Design the shear reinforcement (vertical stirrups) for the beam shown in the figure. Design stirrups based on the shear envelope using the approximate procedure discussed in class. Note that for the overhangs the maximum shear at the support is induced by placing dead and live loads throughout the cantilever portion. Satisfy all strength and spacing requirements specified...
2. The beam in the figure below is to carry 1.6 kips/ft live load and 0.90...
2. The beam in the figure below is to carry 1.6 kips/ft live load and 0.90 kip/ft dead load (including beam weight). Using f: 3000 psi and fy 40,000 psi, investigate the beam for stirrup adequacy according to the approximate ACI method、 li design is not adequate, indicate what revision is necessary. Symmetrical about E span E60 4"」 22" 3ー#7 12" supports 12" # 3 stirrups 9"l___. 9 @ 6" 22'-0" Figure 2: Problem 2.
A rectangular beam having b=16 in and d=26 in spans 28 ft face to face of...
A rectangular beam having b=16 in and d=26 in spans 28 ft face
to face of simple supports. It is reinforced for flexure with 6#11
bars that continue uninterrupted to the ends of the span. It is to
carry service dead load 2.0 kips/ft (including self weight) and
service live load 3.6 kips/ft, both uniformly distributed along the
span. Design the shear reinforcement using vertical U stirrups.
Economize the spacing of stirrups in appropriate number of bands.
Material strengths are...
The T-beam shown in Figure 1 supports the un-factored dead load
of 1.4 kips/ft and live load of 1.5 kips/ft. The dead load does not
include the self-weight of the beam. The material properties are as
follows: fc’=3000 psi; fy=60,000 psi. Design the shear
reinforcement (stirrups). Plot the stirrups distribution along the
span of the beam.
DL= 1.4 kips/ft ; L2=1.5 kips/Ft * 75 Sz=7 X * b=3616. hr-6in k ) انا امه hw-lain + * bw=12 in
COURSE CE 3202 - Design of Concrete Structures SUBJECT HOMEWORK 4 DATE LECTURE # HW 4-2 A simply supported beam with the cross section shown in Fig. P9-5 has a span of 25 ft and supports an unfactored dead load of 1.5 kips/ft, including its own self-weight plus an unfactored live load of 1.5 kips/ft. The concrete strength is 4500 psi. Compute (a) the immediate dead load deflection. (b) the immediate dead-plus-live-load deflection. 16 No. 8 bars Fig. P9-5
Consider the beam subjected to a concentrated load consisting of
2.25 kips of dead load and 5.55 kips of live load at point B. Find
maximum factored beam shear, moment, and deflection.
Consider the beam and loading given below. The beam is subjected to a concentrated load consisting of 2.25 kips of dead load and 5.55 kips of live load at point B. Neglect beam weight. You may use any information from the AISC Manual, a) Draw the general shape...
4) A 100 foot long simply-supported bridge girder supports the unfactored loads shown in the figure. The uniformly distributed dead load, wD, includes the self weight of the girder, and is constant along the full beam length. Concentrated live loads, PL, are applied as shown in the figure. a) Draw factored shear force and factored bending moment diagrams in the spaces provided. Show magnitudes at locations A, B, C, D and E on each diagram.(8) PL = 50k PL-50k WD-2.5...
Figure 2 shows a simply supported beam and the cross section at mid span. The beam supports a uniform service (unfactored) dead load consisting of its own weight plus 1.4 kips/ft and a uniform service (unfactored) live load of 1.5 kips/ft. The concrete strength is 3500 psi, and the yield strength of the reinforcement is 60,000 psi. The concrete is normal-weight concrete. For the midspan section shown in Figure 2, compute фМп and show that it exceeds Mu. WD 1.4...
1. A rectangular beam with b 16 in., d-17 in., and h 20 in. has a clear span of 24 ft. as shown below. The beam has 1 ft. of bearing at each end, so for analysis purposes it is treated as a 25 ft. simple span (to center of bearing at each end). The beam supports an unfactored concentrated live load of P-65 kips. The beam is reinforced with 6-#10 longitudinal bars and #4 stirrups. Material strengths are fc-4,000,...
Please answer question 1 thank you
Reinforced Concrete HW
18%20(2).pdf CEE433- Homework Assignment 9 Assigned: 12 April 2018 Due: 19 April 2018 1. Design the shear reinforcement (vertical stirrups) for the beam shown in the figure. Design stirrups based on the shear envelope using the approximate procedure discussed in class. Note that for the overhangs the maximum shear at the support is induced by placing dead and live loads throughout the cantilever portion. Satisfy all strength and spacing requirements specified...
Please answer question 1 thank you
Reinforced Concrete HW
18%20(2).pdf CEE433- Homework Assignment 9 Assigned: 12 April 2018 Due: 19 April 2018 1. Design the shear reinforcement (vertical stirrups) for the beam shown in the figure. Design stirrups based on the shear envelope using the approximate procedure discussed in class. Note that for the overhangs the maximum shear at the support is induced by placing dead and live loads throughout the cantilever portion. Satisfy all strength and spacing requirements specified...
2. The beam in the figure below is to carry 1.6 kips/ft live load and 0.90 kip/ft dead load (including beam weight). Using f: 3000 psi and fy 40,000 psi, investigate the beam for stirrup adequacy according to the approximate ACI method、 li design is not adequate, indicate what revision is necessary. Symmetrical about E span E60 4"」 22" 3ー#7 12" supports 12" # 3 stirrups 9"l___. 9 @ 6" 22'-0" Figure 2: Problem 2.
A rectangular beam having b=16 in and d=26 in spans 28 ft face
to face of simple supports. It is reinforced for flexure with 6#11
bars that continue uninterrupted to the ends of the span. It is to
carry service dead load 2.0 kips/ft (including self weight) and
service live load 3.6 kips/ft, both uniformly distributed along the
span. Design the shear reinforcement using vertical U stirrups.
Economize the spacing of stirrups in appropriate number of bands.
Material strengths are...
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