Question

The T-beam shown in Figure 1 supports the un-factored dead load of 1.4 kips/ft and live load of 1.5 kips/ft. The dead load does not include the self-weight of the beam. The material properties are as follows: fc’=3000 psi; fy=60,000 psi. Design the shear reinforcement (stirrups). Plot the stirrups distribution along the span of the beam.

DL= 1.4 kips/ft ; L2=1.5 kips/Ft * 75 Sz=7 X * b=3616. hr-6in k ) انا امه hw-lain + * bw=12 in

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v T tt K L= 25 fi DL= 114 kift LL=lisklft b=36 I bin 17 A LU 1 (36x2 Self weight 30x0) +(14427]x150 144 400 lblft 0.4 klft wwa Vc = 8:00158 20 J Fc bod fc= bw=ll = 3000 d=17 : =1 - kip - A ove 0.75 X2X1x3000 x 12 x 17 1000 OVC 16.76 kip ove <vu So, sM901 spacing Ss Au fy 0.75 Sfibu 0.4% 60103 0.75 X 53000x12 48.68 in s = Av fyt sobu 3 0.4% 60X10 50X 12 = 40, Vs = 45.0yX 4597 Те Е1 4. sit # Я 12, одчS stirrups diagram

answered by: ANURANJAN SARSAM
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