For reaction 1, the Kp equals 6.8^5 at 298K. Answer the following questions in alphabetical order...
kinetics and equilibrium 6.
Kimetics and Equlibtiunm 6. For reaction 1, the K, equals 68 × 10s at 298 K. N,(g) + 3H2(g) 근 2 NH,(g) Answer the following questions in alphabetical order to determine the K, for reaction 2 NH,() 1/2 N,(g) + 3/2H,(g) (2) a. What is the equilibtrium constant expres sion for reaction 1 as a K expression? b. What is the equilibrium constant expres- sion for reaction 1 as a K, expression? c. What is the...
12) The equilibrium constant, Kp, is 4.51x10 at 450°C for the reaction represented below. N2(g) + 3 H2(g) 2 NH3(g) a. Write the equilibrium expression, Kp, for the reaction. b.Suppose y ou start out with only reactants in a rigid container. The initial partial pressure of N2(g) is 1.0 atm and that of H2(g) is 1.4 atm. What are the partial pressures of each species when the system reaches equilibrium? c. Find K, for this process at 450°C.
Write the expression for the equilibrium constant Kp for the following reaction. Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example, enter (PNH3)2 as (P NH3)2 . If either the numerator or denominator is 1, please enter 1 PCl3(g) + Cl2(g) ↔ PCl5(g) K = Write the expression for the equilibrium constant Kp for the following reaction. Enclose pressures in parentheses and do NOT write the chemical formula as a subscript. For example,...
The equilibrium constant, Kp, is 4.51 x 10-35 at 450c for the reaction expressed below. N2 (g) + 3H2 (g) equilibrium arrows 2 NH3 (g) a. Write the equilibrium expression for, Kp, for the reaction. b. Supposed you start out with only reactants in a rigid container. The initial partial pressure of N2 (g) is 1 atm and that of H2 is 1.4 atm. What ate the partial pressure of each species when the system reaches equilibrium? Can you explain...
1. Ammonia synthesis reaction 3H2 (g)+N2 (g) = 2NH3(g) takes place in a reactor under constant temperature 673 K. The initial molar ratio between Hz and N2 is 3:1 (no NH, is present initially), and the reaction is allowed to reach equilibrium. (a) If the pressure is kept constant at 1000 kPa, the molar fraction of NH3 at equilibrium is 0.0385. Please calculate Kp. (b) Using Kp obtained from part (a), please calculate the pressure (still kept constant) of this...
1. For the reaction: N2(g)+ 3H2g) 2NH3(g) 4H=-92.4 kJ Complete the Table below by writing: increase, decrease, or no change (2p) к, Partial pressure of NH$(PNH) The temperature is decreased The total volume is increased 2. N;(g)+Og) 2 NO(g) Ke = 4.17 x 104 at 2000 °C. Calculate K for the following reactions: a. N:(g)+O: (g) NOg) (Ip) b. 2 NO(g) N2(g) + O2(g) (Ip) 3. N2(g)+3H:(g)2NH(g) Kp= 2.79 x 10 Calculate Ke at 472 C. (p) at 472 °C....
1. The equilibrium constant, Kp, for the following reaction is 0.497 at 500 K: PCl5(g) <----> PCl3(g) + Cl2(g) Calculate the equilibrium partial pressures of all species when PCl5(g) is introduced into an evacuated flask at a pressure of 1.00 atm at 500 K. PPCl5 = atm PPCl3 = atm PCl2 = atm 2. The equilibrium constant, Kp, for the following reaction is 0.215 at 673 K: NH4I(s) <----> NH3(g) + HI(g) Calculate the equilibrium partial pressure of HI when...
(1). The equilibrium constant, Kp, for the following reaction is 1.80×10-2 at 698K. 2HI(g) =H2(g) + I2(g) If an equilibrium mixture of the three gases in a 15.5 L container at 698K contains HI at a pressure of 0.399 atm and H2 at a pressure of 0.562 atm, the equilibrium partial pressure of I2 is atm. (2). Consider the following reaction: PCl5(g) =PCl3(g) + Cl2(g) If 1.17×10-3 moles of PCl5, 0.217 moles of PCl3, and 0.351 moles of Cl2 are at...
The equilibrium constant, Kp, for the following reaction is 0.110 at 298 K. NH4HS(s) NH3(g) + H2S(g) If ΔH° for this reaction is 92.7 kJ, what is the value of Kp at 212 K? Kp =
Which equilibrium constant expression(s) are for the following reaction. NH3(aq)↔NH3(g) Choose from the list below and enter the letters alphabetical order. (e.g. AH) A) (pNH3)eq F) (pNH3)eq2 B) [NH3]eq G) [NH3]eq-2 C) (pNH3)eq-1 H) (pNH3)eq-2 D) [NH3]eq-1 What is the equilibrium constant expression for the following reaction: Ru2+(aq) + 6NH3(aq)↔Ru(NH3)62+(aq) Choose from the list below and enter the letters alphabetical order. (e.g. For an equilibrium constant of [NH3]6eq[Ru2+]eq enter AH.) A) [Ru2+]eq E) [NH3]-1eq I) [Ru(NH3)62+]6eq B) [NH3]eq F) [Ru(NH3)62+]-1eq...