Question

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3 2 1 0 3 2 1 0 We are going to determine the coefficients for this rational function: [R] Px) C1X+Cyx+CX +Cr4 C11 C12 C13 C14 21 C22 C23 C24 R(x) Qx) C+Cx +x+C P(x) And, here are our boundary conditions: 4 P(3) 91 2 Q(x) P(1) 65 P(O) 64 P(-4) 0 Type f in fuse the IFERROR macro for the values in the yellow-shaded cells (10 pts) t (5 pts) Q(4) 4 Q(2)-2 TType in the appropriate values for the grey-shaded cells (10 pts) T Q-4) 28 T

Answer 1

Pags Solution +4 3 4 give C23 4 RCw with tamd ay Condih' em Pl-4)= 6 PCOJ=64 PC3)=91 P-4) = 28 90-2)= 10 P(2)=-2 To deten ine Coaffi ci'ent ofPex ptay Poeb4 P(3)= 91 0 + 9 2 14N91 Cn+Gr+ C+ 4=6S OC1+ 092 +013 C |4= 64 P(O): 64 PC-4) = 28 -64 Cn + 16 Ci2+4C3+ C14ニ28 in Materix fasm 22 3 1 AX-b C13 64 - (4 C14 28 1 6 -4 to Salve m at lab sima Sがtem geb the We hiuents 4 -3 3= S14=64

Lo?4 72% 09:42 Files MATLAB Drive linsystemsol.m 1 syms x y Z W 2 eqn1 = 27*x + 9*y + 3*z + w == 3 eqn2 = X + y + Z + W == 4 eqn3 = 0*x + 0*y + 0*z + w == 5 eqn4 6 sol = solve( [eqn1, eqn2, eqn3, 7 xSol sol.x 8 ySol 9 zSol sol.z 10 wsol 91 65; 64 = -64*x + 16*y -4*z +w == 28; eqn4], [x, у, = sol.y sol w

tn a tmi Plx) is fory 2 4 - t&4 レク cothvonts Nrw o oelerinine 4 21 +1 C22. 4C 24 4 Ql2)- -2 8 C 4 2 t 2 C23 + C24 =- C74 10 Q(-2) -8 C2」 4 C22-スC23+ - 28 ) -64C, + 16 C22 - ← C23+ C24ニ28 9-4)= wnihen no 9rincar Sys term oove farm mat ix Ax b ) 64 4- 4 4 2 - 2 23 4 -2 -0 C2 4 -4 -64 16 Coshi cientJ he Jet we usmg Matlab C23-3 C21=0 Cr4= 0 7 =て) -3 2 hine f.dynomial 4 3 f64 Thu2 2

Von 4G 71% 09:46 Files MATLAB Drive linsystemsol.m 1 syms x y z w 2 eqn1 3 eqn2 4 eqn3 = -8*x + 4*y - 2*z + w == 5 eqn4 6 sol = solve( [eqn1, eqn2, eqn3, eqn4] , [x, y, 7 xSol sol.x 8 ySol 9 zSol sol.z 10 wsol = 64*x + 16*y + 4*z + w == 4; = 8*x + 4*y + 2*z + W == -2; 10; = -64*x + 16*y -4*z +w == 28; = sol.y = sol.w