Question

CH 3 KCN DMF Cl Br NaH acetone Ho CH3 NaH Br acetone HO 0 NaOH CH3CN KCN CH CN снз-CH2-CH2-8-11-CH3 0 3 (solvent) SO CH can you give the product for each of these reaction?
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Answer #1

alkylhalide reacts with Ken in.presence of DMF it undergoes SN2 reaction

NaH is strong base it removes the proton and forms the nucleophile and it undergoes rearrangement and forms the epoxide

remaining reactions are SN2

C2 CHs wCN SN2 oe CH k<i

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