Question

Use the following information for questions 17 to 26. Egon Spengler is planning a charity benefit gala for his Save the City

How much did crashing that last (fifth) week cost Egon?

$750

$1,000

$1,250

$1,500

0 0
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Answer #1

Answer: $1,250

Explanation: First calculate the duration of all the paths that are required to start activity J

Paths

Time taken by path until activity J

Duration

Crash A

Crash E

Crash B by 2 weeks

Crash I

ABCEHJ

7+5+7+6+4= 29

28

27

25

25

ABCEIJ

7+5+7+6+5= 30 (Critical path)

29

28

26

25

ABCFJ

7+5+7+7= 26

25

25

23

23

ABDGJ

7+5+6+4= 22

21

21

19

19

Total cost of crashing

0

550

550+800= $1350

1350+2000= $3350

3350+ 1250= $4600

  1. Egon should crash Activity A, because Activity A comes on the critical path and activity A has the lowest crashing cost among the activities on critical path.
  2. Similar concept will be used again – select the lowest crashing cost activity of the critical path. Crash E and calculate the total cost.
  3. Now crash B by 2 weeks. Crashing B by two weeks will take the crashing budget to $3,350.
  4. As, ABCEIJ is still critical path we have two remaining activities to crash ‘C or I’. crashing cost of I is less, therefore we crash I.

Crashing fifth week cost Egon $ 1,250

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