Kirchhoff's Laws Consider the circuit below. Assume the internal resistance of each battery is r =...

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Answer 1

Answer #1

on Applying Kirchoff's junction law at the junction,

I2 + I3 = I1 -------(1)

on Applying Kirchoff's loop law in the upper loop,

E2 - (r + R2)*I2 - I1*R1 - I1*r - I1*R3 = 0

15 - (1.9 + 10.6)*I2 - I1*12.5 - I1*1.9 - I1*9 = 0 ------(2)

on Applying Kirchoff's loop law in the lower loop,

E2 - (r + R2)*I2 + I3*R5 + I3*r - E3 + I3*R4 = 0

15 - (1.9 + 10.6)*I2 + I3*18.2 + I3*1.9 - 9 + I3*15 = 0 ----(3)

on solving the above three equations we get,

a) I3 = -0.0180 A

b) I2 = 0.429 A

c) I1 = 0.411 A

d) terminal voltage = 9 - I3*r

= 9 - (-0.018)*1.9

= 9.034 V

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Answer 2

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