1.) The earth completes a circular orbit around the sun with a radius of 93,000,000 miles. What is the speed of the earth around the sun in meters per second? Assume that one year has 365.25 days. Figure out the number of seconds in one year. Put results in scientific notation.
speed = distance covered/ time
= 2pi*r / v
( Note 1mile = 1.609 m and 365.25 days = 365.25*24*60*60 s)
= 2pi*93000000*1.609 / 365.25*24*60*60
= 29.8 m/s
so the speed is 2.98*10^1 m/s
1.) The earth completes a circular orbit around the sun with a radius of 93,000,000 miles....
Need all questions answered. Thank you 1. Driving around the Earth. The distance around the Earth is very nearly 25,000 miles. Imagine that you could drive a car at 60 miles per hour all the way around the Earth. How long would this take? Express your answer in days. 2. Driving to the Moon. The average distance between the Earth and Moon is 239,000 miles. At 60 mph, how long would a drive to the Moon take? Express your answer...
The radius of the earth's orbit around the sun (assumed to be circular) is 1.50×108km, and the earth travels around this orbit in 365 days. Part A What is the magnitude of the orbital velocity of the earth in m/s? Express your answer in meters per second Part B What is the radial acceleration of the earth toward the sun? Express your answer in meters per second squared. Part C What is the magnitude of the orbital velocity of the...
Assume the earth is revolving around the sun in a circular orbit with a radius of 149,600,000km. What is the centripetal acceleration of the earth as it revolves around the sun?
Soleve the problem with steps please! 4. A planet completes one orbit about its sun in 365.24 days. The planet is 93,000,000 miles away from its sun. Compute the planet's speed through space relative to its sun in a. miles per hour. b. kilometers per second 5. A train's speed is 65 miles per hour. The train's wheels are 1.5 meters in diameter. Compute the angular speed of the wheels in revolutions per second
The earth moves around the sun in a nearly circular orbit of radius 1.50 1011 m. During the three summer months (an elapsed time of 7.89 106 s), the earth moves one-fourth of the distance around the sun. (a) What is the average speed of the earth? (b) What is the magnitude of the average velocity of the earth during this period?
Exercise 3.28 The radius of the earth's orbit around the sun (assumed to be circular) is 1.50 x 10° km, and the earth travels around this orbit in 365 days. Part A What is the magnitude of the orbital velocity of the earth in m/s? - Part B What is the radial acceleration of the earth toward the sun? Part What is the magnitude of the orbital velocity of the planet Mercury radius 5.79 x 10 km orbital period =...
A satellite in a circular orbit 500 miles above the surface of the Earth. What is the period of the orbit? You may use the following constants: Radius of the Earth: 4000 miles Gravitational Constant: 66710?11m3(kgs2) Mass of earth: 5981024kg Number of Meters in a mile: 1609 Period= ? seconds
What is the angular kinetic energy of the Earth due to its orbit around the sun? In Homework 10, you found the two main angular velocities of the Earth: one due to the Earth's motion around the sun, and one due to its rotation about its own axis. Now let's figure out the energy and momentum associated with that motion. IVO ALV O a ? For the purposes of this problem, treat the Earth as a solid, uniform sphere with...
The radius of the earth's very nearly circular orbit around the sun is 1.5x10^11m. Find the magnitude of the earth's velocity as it travels around the sun. Assume a year of 365 days. Find the magnitude of the earth's angular velocity as it travels around the sun. Assume a year of 365 days. Find the magnitude of the earth's centripetal acceleration as it travels around the sun. Assume a year of 365 days.
An asteroid is discovered in a nearly circular orbit around the Sun, with an orbital radius that is 2.49 times Earth's. What is the asteroid's orbital period T, its "year," in terms of Earth years? ears