Question

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Problem 2 (1). (35 pts total) 2-0 The inlet volumetric flow rate for an adiabatic compressor is 10 (L/s] of air. The inlet conditions are 120 [kPa) and 20 [deg C). The outlet conditions are 1000 [kPa] and 300 [deg C). Treat air as an ideal gas. Ignore changes in kinetic and potential energy.

Answer 1

Given that in let' volumetric flow rate (g) = 10 Hs 9 = 10 45 = 10x 103 m/s (11-103 m) 9 = 0.01 m3/s. Inlet conditions P = 120 kpa. T = 20°C 293 k' outlet conditions P₂ = 1000 kpa T = 300°C = 593 K (a) Heat transfer into the system is o kilks because it is an adiabatic process. work done = pros mt Here we treat air as an ideal gas. pe=RT, 2 - RTI = 0.287 x 293 120 19 = 0.7 m?/ks Specific volume of air at inlet) Cb) Workdone – 120x on, 1.4-1 8 = 0.7 kg work done = 120x02 [ ( 120 r of air = 14 W= = 174.866 kilks / Here, negative sign indicates that work is done on the systen

(d) Mass flow rate (n) = 9 2, 0.01 0.7 Ñ '= 0.014285 kgfs (es Increase in specific enthalpy of air from inlet to outlet is th=h₂ b = [T₂ -7,] = 1,005 ( 573,- 293) (sh = 281. 4 kJ/kg (ep of air= 1.005 kJ / kg x ). it = 1.005