Question

Question 8 [1.5 pts] Which one of the following statements is correct? 1111111 HO NO11111 Ol Compound E O o Compound E will exhibit mutarotation Compound E will not exhibit mutarotation

Answer 1

Page No. Date Mutarotation & Mutarotation is the change in the rotation because of the change anomers between optie in e two the change an equilibrium Generally, reducing sugar shows muterotation of non-reducing sugar doesn't show mutorstation. Reducing sugar $ Sugar which has free aldehyde group or - free hydroxy group at anomeric carbon. geducing or non-reducing suger. Let's fiost see our given suger Bu Anomeofc carbon (Hydroxy group rengaged in glycosidfc linkage) . HOT OH - H O OH OH Compound Anomeric carbon (free hydroxy group) E So yo our sugh there are two onomeric corrbons, the hydroxy up of one sugar molecule ºg engage in glucose dpc lenkage but hudboxy moup at anomeric curbon of gecond sugar 9 free 80 92 can be easily converted to attes a-form to ß-form So Que comp. E 93 peducible sugar. is As stated above reducible sugar shows mutantation Compound E will exhibit mutartalpon