Homework Answers
We have to find molar concentration (molarity) of acetic acid in 5% vinegar solution.
Given :
Density of vinegar = 1.08 g/mL
Molar mass of acetic acid = 60.05g
Volume of solution = 100mL
Volume of vinegar (acetic acid) = 5mL
Solution :
Mass of acetic acid = density * volume
= 5mL * 1.08 g/mL = 5.4g
Moles of acetic acid = 5.4/ 60.05 = 0.08992
Molarity = no. of moles of solute(mol)/ volume of solution(L)
= 0.08992/0.1
=0.899M
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don’t have any work to support it
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4. Mr. Burnes bought a bottle of vinegar and wondered how concentrated the acetic acid (CH-COOH; mm = 60.05 g/mol) was inside. He titrated it with 0.00182 M NaOH that he found in a general chemistry laboratory. It took 9.90 mL of NaOH to reach the equivalence point. See titration curve on next page. A. What is the concentration of acetic acid if 23.7 mL of vinegar was used for the titration? B. Mr. Burnes bought the economy size bottle...
Calculate the moles of acetic acid, molarity of the vinegar solution, and mass %. of acetic acid in the vinegar using the average of three good trials used to titrate 5.00 mL of the vinegar. You may assume that the density of your vinegar sample is 1.01 g mL^-1. Drain off unused NaOH solution into a clean container and place it into a designated container. Wash the buret two times with regular tap water, then rinse with deionized water, and...
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please show all work. thank you
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a-c
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3. Calculate the molarity of the acetic acid in the vinegar solution for each trial. 4. Calculate the average molarity. 5. Calculate the %mass acetic acid in the vinegar solution. 6. The vinegar for this experiment was store bought Heinz Vinegar. Does your answer to question 5 seem reasonable? 7. Write and appropriate lab procedure for this experiment. Use the data to inform your procedure. % Mass #DIV/0! Name 9 M NaOH Density (g/mL) 0.5167 1.002 Trial 1 Trial 2...
I
think the answer is 3.94% but I don’t know if that is right, and I
don’t have any work to support it
What is the percentage of acetic acid (60.05 g/mol, monoprotic acic) in a sample of vinegar purchased in a supermarket if 40.00 mL of the vinegar required 31.42 m solution for neutralization? Assume that the vinegar solution has a density of 0.960 g/ml. 1. L of 0.8010 M KOH
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