Question

In a recent poll, 350 people were asked if they liked skiing, and 55% said they did. Find the margin of error of this poll, at the 90% confidence level. As in the reading, in your calculations: --Use z1.645 for a 90% confidence interval -Use z=2 for a 95% confidence interval -Use z-2.576 for a 99% confidence interval Give your answer rounded to three decimal places.

Answer 1

Solution Q-) Giveen 0 : 350 6. 651. : 6 Margin of fotos de 1 0 55 CIB) do 1-0.90 - 0.1 BOL=2005 1645] = 1.645 x 0.55 01-0.55) 350 = 1.645% 0.2445 350 -1.645 * 0.026599157 = 0.044 Q-2 de Given 0= 560, $10. 487 4 : P: 24 JPt-f) di 1-0.99: 0.01 20200) 20.005 20.005 : 0.576 . 376 CI = 0.04 2.546 01 (1-0-1). 560 +0.41 8.576 * 10.000315 =0.71 .546 0.019864976 +0.4 + 0.0499 + (0.- 0.0499, 0.4+ 0.0499) (0.650, 0.450)

& Guren D-100 , 7 = 43 P- ổ Hà : 0-3 954. confidence intertal for the coito Kids is PCIP) towe population poopoo Hon of people d: 1-0.95 -0.05 : 20-06 : 20225 - 100 CI = 0.13 0.43C1-0-13) = 0.13 +QxJ0.001911 30.434 0.089 :(064), 0.819) Q. Girlen D: 400 pooportion Ⓡ = 0.65 for 954. confidence lovel, x=1-0.95 005 20:00 =20025 - ď 0.65 0.6501-065) Reis 400 30.651 0.000568753 08630100-6466 -0.65+ 0.0474 : (0.6023, 0.6974

Q_5 Given D=800 12130 point estimate $- ebony 135 - 0.45 Hege D: 1-0.90 :01 20=20= 20:05 = 1.645 90% confidence interval is 300 .: 0.45 * 1645 10:45(1-0.45) = 0.45 + 1.645 10.000805 = 0.45 + 0.0472 ,: 0:4028, 0.4949),