In a recent poll, 380 people were asked if they liked dogs, and 68% said they did. Find the Margin of Error for thi...

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Answer 1

Answer #1

Given that, sample size (n) = 380

sample proportion $(\hat p)$ = 0.68

A 90% confidence level has significance level of 0.10 and critical value is, $Z_{\alpha/2} = 1.645$

We want to find, the margin of error (E),

$E = Z_{\alpha/2} *\sqrt {\frac {\hat p *(1-\hat p)}{n}} = 1.645 * \sqrt {\frac {0.68*(1-0.68)}{380}} = 0.0394$

=> Margin of Error (E) = 0.0394

Answer 2

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