In a recent poll, 230 people were asked if they liked dogs, and
80% said they did. Find the margin of error of this poll, at the
99% confidence level.
Give your answer to three decimals
Solution :
Given that,
n = 230
Point estimate = sample proportion = = 0.80
1 - = 0.20
At 99% confidence level the z is ,
= 1 - 99% = 1 - 0.99 = 0.01
/ 2 = 0.01 / 2 = 0.005
Z/2 = Z0.005 = 2.576
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 2.576 * (((0.80 * 0.20) / 230)
= 0.068
The margin of error of this poll, at the 99% confidence level is 0.068.
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