By gas equation
=
... (1)
Given, initial pressure( P1 ) = 25 atm, initial temperature ( T1 )
= (- 50 + 273.15) K = 223.15 K.
let initial volume is V1
now, final volume (V2) = 25 L.
Final pressure (P2) = 15 atm
Final temperature (T2) = ( 30.00 + 273.15 ) K = 303.15 K.
using Eq.1
=
Or, V1 = (15×25×223.15)/(25×303.15) L.
Or, V1 = 11 L (2 significant figures)
So, initial volume of the gas was 11 L.
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