Question

How do i convert the following C program into MIPS assembly?

int main(void) 
{
 short var1[4] ={5, 8, 13, 6}; 
 short var2[4]= {16, 4, 7, 15}; 
 short result[4]={0}; 
for (int i=0 ; i< 4; i++) 
result[i] = var1[i] - var2[i]; 
}

Answer 1

• # int var1[4] ={5, 8, 13, 6};
  # int var2[4]= {16, 4, 7, 15};
  # int result[4]={0};
  #
  # for (int i=0 ; i< 4; i++)
  #   result[i] = var1[i] - var2[i];
  
  
  .data
     var1:  .word 5, 8, 13, 6
     var2:  .word 16, 4, 7, 15
     result:    .word 0, 0, 0, 0
  
  .text
     la $s0, var1
     la $s1, var2
     la $s2, result
  
     li $t0, 0  # i = 0
     for:   bge $t0, 4, end
  
        sll $t1, $t0, 2
        add $t1, $s0, $t1
        lw  $t1, 0($t1)       # $t1 = var1[i]
  
        sll $t2, $t0, 2
        add $t2, $s1, $t2
        lw  $t2, 0($t2)       # $t1 = var2[i]
  
        add $t1, $t1, $t2  # $t1 = var1[i] - var2[i]
  
        sll $t3, $t0, 2
        add $t3, $s2, $t3
        sw  $t1, 0($t3)       # result[i] = var1[i] - var2[i]
  
        addi $t0, $t0, 1   # i++
        j for
     end