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#include "stdio.h" #include <iostream> int main() { unsigned char var1 = 4; unsigned short int var2...
Solve using C programming 3. lf you are given this code. #include <stdio.h> int main() int var1, var2; int sum; printf("Enter number 1:\n "); scanf("%d",&var1); printf("Enter number 2:In ); scanf("%d",&var2); sum-var1+var2; printf ("Vnsum of two entered numbers : %d", //printf ("Output: %d", res); sum); return e; Modify this code by creating a function called "addition". Make the arguments of the functions numberl and number 2. Add the two values in the function. Return a value called "result". Print "result" in...
main.c #include <stdio.h> int main() { Tong Tong int x = 1234567890000; char y = (char) x; printf("%d\n", y); Compile and run the above main.c file. a) Indicate the compiler command you would use to compile this program. Do any of the following flags affect the compilation? -Wall -Werror -pedantic -Woverflow b) Indicate any discrepancy between expected and actual behavior, and as a programmer, how to construct best practices to avoid this deviation. c) What happens if we do not...
//countingAnimals.cpp C++ #include <iostream> #include "Animal.h" using namespace std; int Animal::count = 0; int main(int argc, const char * argv[]) { Animal myAnimal; Animal anotherAnimal; cout << Animal::count << endl; return 0; }
How do i convert the following C program into MIPS assembly? int main(void) { short var1[4] ={5, 8, 13, 6}; short var2[4]= {16, 4, 7, 15}; short result[4]={0}; for (int i=0 ; i< 4; i++) result[i] = var1[i] - var2[i]; }
PLease explain output of these two programs: 1. #include <stdio.h> typedef struct { char *name; int x, y; int h, w; } box; typedef struct { unsigned int baud : 5; unsigned int div2 : 1; unsigned int use_external_clock : 1; } flags; int main(int argc, char** argv){ printf("The size of box is %d bytes\n", sizeof(box)); printf("The size of flags is %d bytes\n", sizeof(flags)); return 0; } 2. #include <stdio.h> #include <string.h> /* define simple structure */ struct { unsigned...
In C, thanks. #include <stdio.h> void set-flag (unsigned int* flag-holder , int flag-position); void unset-flag (unsigned int * flag-holder, int flag-position); int check-flag (unsigned int flag-holder , int flag-position); void display -32_flags (unsigned int flag-holder); int main(int argc, char* argv (1) unsigned int flag -holder = 0; set-flag (& flag-holder, 3); set-flag (& flag-holder, 16); set-flag (& flag-holder, 31); display-32-flags (flag-holder); unset-flag(& flag-holder , 31); unset-flag (& flag-holder, 3); set-flag (& flag-holder , 9); display-32-flags (flag-holder ); return 0; Write...
why is correct the output of this code? #include <stdio.h> int main( void ) { char val[] = "one"; if (val[1] = 'o') printf("correct"); else printf("incorrect"); }
What is printed when the following code is executed? #include <stdio.h> int main() { for (int i=3, j=5; i>=0; i-=2, j+=j*i) { printf("%d", j); منم }
#include <stdio.h> int main(int argc, char *argv[]) { int i; for (i = argc - 1; i > 0; i--) printf("%s ", argv[i]); printf("\n"); return 0; } can you explain this code in c and why use this function
The operating system is Ubuntu 18.04 hello.c #include <stdio.h> int main(int argc, char *argv[]) { printf("Hello world!\n"); return 0; } syscall-hello.c #include <unistd.h> #include <sys/syscall.h> char *buf = "Hello world!\n"; int main(int argc, char *argv) { size_t result; /* "man 2 write" to see arguments to write syscall */ result = syscall(SYS_write, 1, buf, 13); return (int) result; }Download and compile hello.ce and syscall-hello.com. Compile them statically and dynamically. How do the library and system calls produced by them compare...