Solution:
Suppose you draw 5 cards from the standard 52 card deck,
The probability that hand contains at least two aces or at least kings.
P(at least two aces or at least two kings)
= P (at least two aces) + P (at least two kings) - P (at least two aces at least two kings)
Now,
P (at least two aces) = P (2 aces, 3 others) + P (3 aces, 2 others), + P (4 aces, 1 other)
P (at least two kings) = P (2 kings, 3 others) + P (3 kings, 2 others), + P (4 kings, 1 other)
P (at least two aces at least two kings) = P (2 aces, 3 kings) + P (3 aces, 2 kings) + P (2 aces, 2 kings, 1 other)
Therefore,
P (at least two aces or at least two kings)
= P (at least two aces) + P (at least two kings) - P (at least two aces at least two kings)
Note : Hope you understand the solution, kindly upvote.
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