Question

how would i solve for the m/m% of Na+ in the food sample from my calibration curve? ive attatched my other data. thank you in advance!

5. Area under the curve 1189945 7,00 m/m% of Nat in Food Sample from calibration curve unrounded (show calculation) m/m% of Nat in Food Sample from calibration curve

Answer 1

To know m/m % of Na⁺ in food sample corresponding to the area under the curve which is 11899457 ,

we fist have to find calibration equation by plotting True m/m % of Na⁺ unrounded in Y-axis and Area under the curve in X-axis

Hence, The plot is

Area under the curve Calibration curve True m/m % Na^+ unrounded 7130230.5 0.23515007 24412348 0.746014388 33852664 1.0402507 66645384 2.014639 98886976 2.977748 True m/m % Naat unrounded y = 3E-08x + 0.0218 R2 = 1 20000000 40000000 50000000 80000000 100000000 120000000 Area under the curve

The calibration equation is , y = 3 * 10^-8 x + 0.0218 , and R² = 1

So, now putting area under the curve 11899457 at x position in calibration we get,

y = 3 * 10^-8 * 11899457 + 0.0218

=> y = 0.3788

Hence, for the corresponding area under the curve 11899457 , we get m/m % of Na⁺ unrounded is 0.378

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