Question

"Black Box" 5.1 The myDAQ power source is non-ideal. As such, a Thevenin Equivalent circuit may be constructed as a more accurate model. 5.2 Experimentally determine the Thevenin Equivalent Resistance and Thevenin Voltage of the myDAQ 5V power supply. Verify the accuracy of the Thevenin Equivalent circuit by measuring the voltage across a chosen load resistor. (Hint: To model the power source, you can test it for two different load resistors e.g. 100082 and 47052. Do not short the output of the power supply.) 5.3 Experimentally determine the Norton Equivalent Resistance and Norton Current. Verify the accuracy of the equivalent by measuring the current across a chosen load. - To model the Norton equivalent, use the following loads: 100022 and 47032 - Consider that you will have to readjust the current after switching the load R12 [9]- . 63,892 461 Vrh [V] RTH [92] RLI [2] 1001 VR [V] VR2 [V] 4.69 4.71 IRL1 [mA] IRL2 [mA] 4.70 10.10 In[mA] RN [2]

i have experimentally measured the values in the table so far. i need to use that information to calculate the remaining items which are whited out. how do it do this? could you write the answers along with a bit of explaination thank you very much!

Answer 1

RLOAD Thevenin Equivalent RTH ZRN RLOAD Nodon Equivalent We have been (FORTABLE ! !) given load I'ar for (R = looks ļ= 4612 - so we will find out Either of AS Both can be calculated it th ARThor IN ORN either of them is found once!!

RTM Real Clood) So using Thevenin equivalent (as AB ove) y using KVL for R2, = 1001.2 (lood? 4 Vith - IRTA - VRL =0 Ie) & Vinz Irth + VR2 IZIRL elements in series) = (1 z 4.70 MAT (from table) & VR 24.69 v → Pth z 4.7 MA x Rth + 4.691 – 0 using KVL for TR22 = 46122 (load) d Vth - I Rih - VRL, zo si Uth = (10-1 MAX Rh) + 4.711 - 2 (from table Ilze ² 10.1 MA solving 0 A ® for 2 unkowns V ART VTH = 4.672 v IRTHI Z 13-703 ut IN 2 VTVRT Z 4,6724240,-26) Amps RN z RTH = 3.7032 VR22 2 4.710
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