The solution to problem 2-2 (a):
Year |
The average percentage of good parks |
Good quality |
Good quality |
Good quality % |
Product Yield |
Product Yield |
|
2012 |
78% |
30851*0.78+30851(1-0.78)(0.39) |
26710.8 |
(26710.8/30851)*100 |
87 |
30851(0.87)+30851(1-0.87)(0.39) |
28405 |
2013 |
80% |
30851*0.80+30851(1-0.80)(0.39) |
27087.2 |
(27087.18/30851)*100 |
88 |
30851(0.88)+30851(1-0.88)(0.39) |
28593 |
2014 |
82% |
30851*0.82+30851(1-0.82)(0.39) |
27463.6 |
(27463.56/30851)*100 |
89 |
30851(0.89)+30851(1-0.89)(0.39) |
28781 |
2015 |
84% |
30851*0.84+30851(1-0.84)(0.39) |
27839.9 |
(27839.94/30851)*100 |
90 |
30851(0.9)+30851(1-0.9)(0.39) |
28969 |
2016 |
86% |
30851*0.86+30851(1-0.86)(0.39) |
28216.3 |
(28216.32/30851)*100 |
91 |
30851(0.91)+30851(1-0.91)(0.39) |
29157 |
The solution to problem 2-6
Process yield = 0.91*0.71*0.72*0.91*0.99*0.7 = 0.29
Product yield = 0.29* 905 = 265.5 = 266 cabinets
Product input required to achieve final weekly product yield of 905 cabinets = 905/0.29 = 3120.689 = 3121
Problem 2.2 (Part Level Submission) The Backwoods American Company produces approximately 30,851 parkas annually. The quality-management...
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