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Question 2 The figure provided shows a section of a very long rod of radius a = 2.36 mm and linear charge density 3.53 nC/m.

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Answer #1

The electric field

Applying Gausss Law & E da = Sade - done E & da = al Eo E (200l) = साह E = 3.53X10-9 21 X 8.85X1512X5.67153 E11:2X10 TE = 1.

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