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Part A)

Find the current, I1 (in mA) in the circuit shown below. Assume Vs= 3.8V and R1=R2=R3=9.4 k ohm.

Part B)

The resistance of the resistor network between the nodes A and B is measured using a multimeter. What is the resistance measured (in k ohm)? Assume R1=R2=R3=R4=6.6k ohm

A В 3 ww

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Answer #1

given data Vs = 3.8V Ri=R2= R3 = 9.4K ohm = 94002 According to problem soup Ris R2 are in parallel, then R, R2 - RitR2 9.449.Page No. Date ? I= 0.2695 mA R2 I, I Ri+R2 9400 x0.2695 9400+ 9400 1 0.13475 MA I= 0.13475 mA (B) And R2, Ru, R3 are in serie

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