Question

1-Hello, Can I get help solving the following question? It is specialized in physics 2, I tried to solve it but I couldn't, I would appreciate any help, thanks! A network of ten capacitors are shown in the figure below, where the capacitances are as follows C6 C9-7uF, and C10 15uH. C5 C6 C7 C10 C8 C4 C9 a) Find the equivalent capacitance Ceq between points a and b in the capacitor network of the figure. If a potential difference of Vab = 12 Vis applied across points a and b, calculate the charge on Ceq b) c) Find the energy stored in Ceq

Answer 1

C_6, C_10, C_4 ARE IN SERIES, HENCE THERE EQUIALENT 1/C� = 1/C_6 + 1/C_10 + 1/C_4 = 1/7 + 1/15 + 1/7 rightdoublearrow C� = 2.84 mu F C_7 AND C_8 ARE ALSO IN SERIES. HENCE THERE EQUI. 1/C�� = 1/C_7 + 1/C_8 = 1/3 + 1/5 rightdoublearrow C�� = 1.88 mu F C_3 AND C_5 ARE IN SERIES THERE EQUIVALENT 1/C��� = 1/C_3 + C_7 = 1/7 + 1/3 rightdoublearrow C��� = 2.10 mu F C_1 AND C_4 ARE IN SERIES. THERE EQUIVALENT 1/C���� = 1/C_1 + 1/C_4 = 1/3 + 1/5 rightdoublearrow C���� = 1.88 mu F NOW SIMPLE CRT IT \r\n C_2 AND C���� ARE IN PARALLEL AND THEN THERE COMBINATION IS IN SERIES WITH C��� therefore THERE EQUIVALENT C����� = (C���� + C_2)C���/(C���� + C_2) + C��� = (1.88 + 5)2.10/(1.88 + 5) + 2.10 = 14.448/8.98 = 1.61 mu F Now C�, C�� AND C����� ARE IN PARALLEL. therefore C_eq = C� + C�� + C����� =