An acid with molar mass 116.08 g/mol contains by mass, 41.4 %0, 3.47 %H, and 55.1...

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Answer 1

Answer #1

lo Molos most of acid = 16.088/red mass of C = 41.4% - 41.4 166.08 - 48.05g 14 Hath 3.47x116.08 = 4.o 2 g 0 = 55.1 116-08

Answer 2

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