Question

Answer to part C??? (Remember sig figs)

b. Based on the results from Solution 2, calculate the concentration of ascorbic acid in Solution 1 (in mM). CIVにC2V2 x) (20mL) (0.04 75) (ioomL) x) 20m L 4.75 c. Based on the results from Solution 1, calculate the mass of ascorbic acid in the original vitamin C tablet (in mg).

(PART A)

Answer 1

So here we have given millimolar concentration and also volume in ml so from the molarity and the volume we can easily calculate the millimoles of the ascorbic acid present and from the millimoles and the molar mass we can find out amount of ascorbic acid present as shown below;

So the concentration is 0.2375 mM and volume is 20 ml So, millimoles = molarity times volume millimoles = 0.2375 mM times 20 ml millimoles = 4.75 mMoles So, molar mass of ascorbic acid is 176.1291 mol So, moles = no.of grams of ascorbic acid/molar mass 4.75/1000 = 4.75 times 10^3 moles = no.of grams/176.1291 mol no of grams = 4.75 times 10^-3 times 176.12 = 0.83657 grams So, In milligrams = 0.83657 times 1000 = 836.57 mg = 837 mg