Part B
1) Grams of Vitamin C in Erlenmeyer
Volume of NaOH in Erlenmeyer
Trail 1: Final - Initial = 32.50 - 0 = 32.50 ml
Trail 2: Final - Initial = 32.70 - 0 = 32.70 ml
Moles of NaOH in Erlenmeyer (molarity is 0.100M)
Trail 1: moles of NaOH = 0.100 M × 0.0325 L = 0.00325 mol
Trail 2: moles of NaOH = 0.100 M × 0.0327 L = 0.00327 mol
As reaction ratio of NaOH and Vitamin C is 1:1, so NaOH reacted with same moles of Vitamic C, as moles of NaOH
Trail 1: moles of Vitamin C = 0.100 M × 0.0325 L = 0.00325 mol
Trail 2: moles of Vitamin C = 0.100 M × 0.0327 L = 0.00327 mol
Since molar mass of Vitamin C is 176.12 g/mol
grams = moles × molar mass
Trail 1: grams of Vitamin C = 176.12 g/mol × 0.00325 mol = 0.57 g
Trail 2: grams of Vitamin C = 176.12 g/mol × 0.00327 mol = 0.58 g
2) Grams of Vitamin C per tablet
500mg of 1 tablet Vitamin C contains less than 1 g of Vitamin C. From above calculation
Trial 1: grams of Vitamin C per tablet is 0.57 g
Trial 2: grams of Vitamin C per tablet is 0.58 g
3) %Error of grams of Vitamin C per tablet to the tablet dose
%error = (grams of Vitamin C - tablet dose ) / tablet dose × 100
Trail 1: %error = (0.57 g - 0.5 g) / 0.5 g × 100 = 14%
Trail 2: %error = (0.58 g - 0.5 g) / 0.5 g × 100 = 16%
4) %composition of Vitamin C per tablet is calculated using below equation
%composition of Vitamin C = (mass of Vitamin C per tablet / mass of 1 tablet given ) × 100
Trial 1: %composition of Vitamin C = (0.57g / 0.859) × 100 = 66.36 %
Trial 2: %composition of Vitamin C = (0.58g / 0.859) × 100 = 67.52 %
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