A GRADUATED CYLINDERCONTAINS 123mLOF WATER. A 45.0g PIECE OF SILVER (d=10.49g/L) IS ADDED. WHAT IS THE...
A GRADUATED CYLINDERCONTAINS 123mLOF WATER. A 45.0g PIECE OF SILVER (d=10.49g/L) IS ADDED. WHAT IS THE NEW WATER LEVELOF THE GRADUATED CYLINDER, IN mLOF THE CYLINDER? D=m/V
Homework Answers
We know that, Density = mass/volume
or d=m/v where mass m is in grams, volume v is in litres, thus units of density are g/L
Given that density of silver = 10.49g/L and its mass = 45g
therefore, volume v =m/d = 45/10.49 = 4.289 Litres 
4.29 Litres
as 1L = 1000ml
4.29L = 4290 ml
Earlier, the graduated cylinder had 123ml of water. On addition of the silver piece, new volume will be 123+4290= 4413ml
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