Q) Hi, Can you please answer the question using clear detailed steps and definitions so I can better understand it? Thank you so much! :)
Q) Hi, Can you please answer the question using clear detailed steps and definitions so I...
Question 3. Let Q be the solid hemisphere bounded by x + y² + 2 = 1 for 2 > 0 and by the plane z = 0, and let F = xi+yi + zk be a vector field. Verify the divergence theorem for Q and F by answering parts (a) and (b) below. Part (a) (5 points). Find the value of the triple integral of the divergence of F over the solid hemisphere Q. Part (b) (10 points). Evaluate...
PLEASE SHOW AND EXPLAIN ALL STEPS FOR ALL 3 PARTS......I'M LOST......THANKS SO MUCH!! r 1 Given the vector field in space F(x, y, z) = xi + yj + zk or more conveniently, (x2 + y2 + 22)3/2 F(r) =3 = f where r = xi + yj + zk and r = = 1|r1| Vr2 + y2 + x2 (instead of p) (a) (10 pts) Find the divergence of F, that is, V.F. =V (b) (10 pts) Directly evaluate...
please just the final answer for both Evaluate the surface Integral || 5. ds for the given vector fleld F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation. F(x, y, z) = yi - xj + Szk, S is the hemisphere x2 + y2 + y2 = 4, 220, oriented downward 26.677 X Evaluate the surface integral llo F.ds for the given vector field F...
please answer the following question so a beginner can understand. 5.3 Surface integral of vector fields 5.4 Stokes' Theorem C simple closed, positively oriented w.r.t. S 5 5.5 Divergence Theorem S is outward oriented boundary of E, Example 8. Let D be the portion of z = 1-x2-y2 inside x2 + y2-1, oriented up. F-yi+zj-xk, compute JaF -ds. 5.3 Surface integral of vector fields 5.4 Stokes' Theorem C simple closed, positively oriented w.r.t. S 5 5.5 Divergence Theorem S is...
#4 please 3. (12 pts). (a) (8 pts) Directly compute the flux Ф of the vector field F-(x + y)1+ yj + zk over the closed surface S given by z 36-x2-y2 and z - 0. Keep in mind that N is the outward normal to the surface. Do not use the Divergence Theorem. Hint: Don't forget the bottom! (b) (4 pts) Sketch the surface. ts). Use the Divergence Theorem to compute the flux Ф of Problem 3. Hint: The...
Hi, I'm having trouble solving this problem... Could you please solve it using clear detailed steps so that I can better understand how to tackle it next time? Thanks! :) Consider the following image. (Take q1 +2.95 nC and q28.44 nC.) gh 42 (a) Find the net electric flux through the cube shown in the figure above. N m2/c (b) Can you use Gauss's law to find the electric field on the surface of this cube? Yes No Explain
Hi, I'm having trouble solving this problem... Could you please solve it using clear detailed steps so that I can better understand how to tackle it next time? Thanks! :) A charge of 100 AHC is at the center of a cube of edge 75.0 cm. No other charges are nearby. (a) Find the total flux through each face of the cube. (b) Find the flux through the whole surface of the cube N m2/c (a) would change O (b)...
good evening. i need help with this calculus question. i will thumbs up your answer. or more conveniently, Given the vector field in space F(x, y, z) = ri+yj + zk (x2 + y2 + 22)3/2 F(r) where r = ri+yj + zk and r= ||1|| = r3 r 22 + y2 + 22 (instead of p) (a) [10 pts] Find the divergence of F, that is, V.F. (b) [10 pts] Directly evaluate the surface integral F. NdS where S...
good evening. i need help with this calculus question. i will thumbs up your answer. or more conveniently, Given the vector field in space F(x, y, z) = ri+yj + zk (x2 + y2 + 22)3/2 F(r) where r = ri+yj + zk and r= ||1|| = r3 r 22 + y2 + 22 (instead of p) (a) [10 pts] Find the divergence of F, that is, V.F. (b) [10 pts] Directly evaluate the surface integral F. NdS where S...
It is divergence free and an open surface so I think you have to think of it as a closed surface and subtract the flux of the unit circle. Thank you! 6 7. (4 pts) Without using a calculator, find the flux of the vector field } = (1 + 21+2) 7 + ze +17+ (x² + y2) through S: the portion of the open surface x2 + y2 = 1 – 24 (as shown) above the ty-plane, oriented downward.