We know that,
Delta G° = - R * T * ln Kc
Where Delta G° is standard Gibbs free energy. R is gas constant with value 8.314 J/mol K . T is temperature in Kelvin and Kc is equilibrium constant.
Delta G° = - 24.7 KJ = -24700 J
T = 25° C = 298 K
Now,
-24700 = - 8.314 * 298 * ln Kc
ln Kc = 9.96944
Kc = e^(9.96944) = 2.14*10^4 ... Answer
Hence, option (a) is correct.
Which of the following is the correct equilibrium constant for the following reaction run at pH...
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