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5. Calculate the equilibrium constant for the reaction, Glucose-1-phosphate + H2O + glucose +...
Calculate the equilibrium constant K'eq for each of the following reactions at pH 7.0 and 25 °C, using the AG'0...
Calculate the equilibrium constant K'eq for each of the following reactions at pH 7.0 and 25 °C, using the AG'0 values in the given Table. glucose 6-phosphatase (a) Glucose 6-phosphate + H20 glucose P B-galactosidase (b) Lactose + H20 glucose galactose fumarase fumarateH2O (c) Malate Standard Free-Energy Changes of Some Chemical Reactions AG Reaction type (kI/mol) (kcal/mol) Glycosides MaltoseH,0 Lactose+ H,0 2 glucose glucose +galactose 15.5 15.9 -3.7 -3.8 Rearrangements Glucose 1-phosphate glucose 6-phosphate Fructose 6-phosphate glucose 6-phosphate -7.3 -1.7...
ore: 1593/2300 Resources 1 Give Up? Hint 823 Phosphoglucoisomerase interconverts glucose 6-phosphate to, and from, glucose...
ore: 1593/2300 Resources 1 Give Up? Hint 823 Phosphoglucoisomerase interconverts glucose 6-phosphate to, and from, glucose 1-phosphate. phosphoglucoisomerase glucose 6-phosphate = glucose 1-phosphate After mixing equal amounts of the two molecules, the solution achieved equilibrium at 25 'C. The concentration at equilibrium of glucose 1-phosphate is 0.01 M, and the concentration at equilibrium of glucose 6-phosphate is 0.19 M. Calculate the equilibrium constant, Keg, and the standard free energy change, AG', of the reaction mixture. Ko = AG' = kJ....
Which of the following is the correct equilibrium constant for the following reaction run at pH...
Which of the following is the correct equilibrium constant for the following reaction run at pH = 7.00 and 25.0 degrees C? The (delta)Gº' = -24.7 kJ/mol glucose-1-phosphate (G1P) + H20 = glucose + H2PO4 Keq = 2.14 x 104 Keq = 4.60 x 103 Keq = 4.68 x 10-5 Keq = 2.17 x 10-4
1) SHOW WORK 12. During glycolysis, glucose 1-phosphate is converted to fructose 6-phosphate in two successive...
1) SHOW WORK
12. During glycolysis, glucose 1-phosphate is converted to fructose 6-phosphate in two successive reactions: glucose 1-phosphate → glucose 6-phosphate glucose 6-phosphate + fructose 6-phosphate AG'' = -7.1 kJ/mol AG'º = +1.7 kJ/mol 13. The standard free-energy changes for the reactions below are given. phosphocreatine → creatine + Pi ATP → ADP + Pi AG" = 43.0 kJ/mol AG" = -30.5 kJ/mol What is the overall AG' for the following reaction? Iw a dee Hydrolysis of 1 M...
The enzyme hexokinase catalyzes the following reaction: Glucose + ATP ↔ Glucose 6-phosphate + ADP For...
The enzyme hexokinase catalyzes the following reaction: Glucose + ATP ↔ Glucose 6-phosphate + ADP For this reaction, ΔG° = +16.7 kJ/mol a. Calculate the equilibrium constant for this reaction at 25 °C. Is this reaction spontaneous under standard conditions at this temperature? Calculate the ΔG if the reaction temperature was 25 °C and the concentrations are: glucose, 55.0 mM,; ATP, 5.00 mM; ADP, 1.00 mM; and glucose 6-Phosphate, 0.100 mM. Would the reaction be spontaneous under the conditions of...
Consider this reaction: Glucose + Pi ⇔ glucose 6-phosphate + H2O, ∆Go = +3 kcal/mol Under physiologic conditions, [gluco...
Consider this reaction: Glucose + Pi ⇔ glucose 6-phosphate + H2O, ∆Go = +3 kcal/mol Under physiologic conditions, [glucose] = 5 mM, [Glucose 6-phosphate] = 83 mM, and [Pi] = 1 mM. Under these conditions, will the reaction above go spontaneously from left to right? If not, what would the concentration of glucose need to be for the reaction to go from left to right, if the concentrations of the other reactants and products are as stated? Please show all...
The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. 0 Calculate AG for the r...
The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. 0 Calculate AG for the reaction 24.64 kJ/mol Calculate AG for the reaction when the partial pressures are PH, 0.28 atm, Pco,0.75 atm, H2O = 0.65 atm, and CO*. Pco-1.16 atm.
The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. 0 Calculate AG for the reaction 24.64 kJ/mol Calculate AG for the reaction when the partial pressures are PH, 0.28 atm, Pco,0.75 atm,...
can I get help with ALL THREE of these questions, please? A reaction has a standard...
can
I get help with ALL THREE of these questions, please?
A reaction has a standard free-energy change of -17.30 kJ mol-'(-4.135 kcal mol-'). Calculate the equilibrium constant for the reaction at 25°C. Kog What is the value of K for this aqueous reaction at 298 K? A+B= C+D AG° = 14.81 kJ/mol K= For a particular reaction at 189.0 °C, AG = -424.14 kJ, and AS = 149.31 J/K. Calculate AG for this reaction at -101.8 °C. AG =...
Consider the given interconversion, which occurs in glycolysis. fructose 6-phosphate glucose 6-phosphate K1.97 What is AG...
Consider the given interconversion, which occurs in glycolysis. fructose 6-phosphate glucose 6-phosphate K1.97 What is AG for the reaction (K measured at 25 °C)? AG -1680.9 kJ/mol If the concentration of fructose 6-phosphate is adjusted to 1.4 M and that of glucose 6-phosphate is adjusted to 0.75 M, what is AG? AG =-4402.59 kJ/mol Which statements are consistent with the conditions at which AG is measured? The temperature is 273 K. The initial concentrations of reactant and product are 1...
CHEM 351 Biochemistry I - Fall 2018 Study Problems for Metabolism and Glucose Catabolism For the...
CHEM 351 Biochemistry I - Fall 2018 Study Problems for Metabolism and Glucose Catabolism For the reaction: aA + bB =cC + dD Gibbs free energy: AG = AG" + RT IN THE glucose + glucose 6-phosphate + H20 1. The equilibrium constant for phosphorylation of glucose is: Ke = 3.97 x 10- a. Calculate the standard Gibbs free energy for the uncatalyzed reaction. b. Use the physiological concentrations for glucose (2.0 mm) and inorganic phosphate (20 mM) to determine...
Calculate the equilibrium constant K'eq for each of the following reactions at pH 7.0 and 25 °C, using the AG'0 values in the given Table. glucose 6-phosphatase (a) Glucose 6-phosphate + H20 glucose P B-galactosidase (b) Lactose + H20 glucose galactose fumarase fumarateH2O (c) Malate Standard Free-Energy Changes of Some Chemical Reactions AG Reaction type (kI/mol) (kcal/mol) Glycosides MaltoseH,0 Lactose+ H,0 2 glucose glucose +galactose 15.5 15.9 -3.7 -3.8 Rearrangements Glucose 1-phosphate glucose 6-phosphate Fructose 6-phosphate glucose 6-phosphate -7.3 -1.7...
ore: 1593/2300 Resources 1 Give Up? Hint 823 Phosphoglucoisomerase interconverts glucose 6-phosphate to, and from, glucose 1-phosphate. phosphoglucoisomerase glucose 6-phosphate = glucose 1-phosphate After mixing equal amounts of the two molecules, the solution achieved equilibrium at 25 'C. The concentration at equilibrium of glucose 1-phosphate is 0.01 M, and the concentration at equilibrium of glucose 6-phosphate is 0.19 M. Calculate the equilibrium constant, Keg, and the standard free energy change, AG', of the reaction mixture. Ko = AG' = kJ....
Which of the following is the correct equilibrium constant for the following reaction run at pH = 7.00 and 25.0 degrees C? The (delta)Gº' = -24.7 kJ/mol glucose-1-phosphate (G1P) + H20 = glucose + H2PO4 Keq = 2.14 x 104 Keq = 4.60 x 103 Keq = 4.68 x 10-5 Keq = 2.17 x 10-4
1) SHOW WORK
12. During glycolysis, glucose 1-phosphate is converted to fructose 6-phosphate in two successive reactions: glucose 1-phosphate → glucose 6-phosphate glucose 6-phosphate + fructose 6-phosphate AG'' = -7.1 kJ/mol AG'º = +1.7 kJ/mol 13. The standard free-energy changes for the reactions below are given. phosphocreatine → creatine + Pi ATP → ADP + Pi AG" = 43.0 kJ/mol AG" = -30.5 kJ/mol What is the overall AG' for the following reaction? Iw a dee Hydrolysis of 1 M...
The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. 0 Calculate AG for the reaction 24.64 kJ/mol Calculate AG for the reaction when the partial pressures are PH, 0.28 atm, Pco,0.75 atm, H2O = 0.65 atm, and CO*. Pco-1.16 atm.
The equilibrium constant (Kp) for the reaction below is 4.40 at 2000. K. 0 Calculate AG for the reaction 24.64 kJ/mol Calculate AG for the reaction when the partial pressures are PH, 0.28 atm, Pco,0.75 atm,...
can
I get help with ALL THREE of these questions, please?
A reaction has a standard free-energy change of -17.30 kJ mol-'(-4.135 kcal mol-'). Calculate the equilibrium constant for the reaction at 25°C. Kog What is the value of K for this aqueous reaction at 298 K? A+B= C+D AG° = 14.81 kJ/mol K= For a particular reaction at 189.0 °C, AG = -424.14 kJ, and AS = 149.31 J/K. Calculate AG for this reaction at -101.8 °C. AG =...
Consider the given interconversion, which occurs in glycolysis. fructose 6-phosphate glucose 6-phosphate K1.97 What is AG for the reaction (K measured at 25 °C)? AG -1680.9 kJ/mol If the concentration of fructose 6-phosphate is adjusted to 1.4 M and that of glucose 6-phosphate is adjusted to 0.75 M, what is AG? AG =-4402.59 kJ/mol Which statements are consistent with the conditions at which AG is measured? The temperature is 273 K. The initial concentrations of reactant and product are 1...
CHEM 351 Biochemistry I - Fall 2018 Study Problems for Metabolism and Glucose Catabolism For the reaction: aA + bB =cC + dD Gibbs free energy: AG = AG" + RT IN THE glucose + glucose 6-phosphate + H20 1. The equilibrium constant for phosphorylation of glucose is: Ke = 3.97 x 10- a. Calculate the standard Gibbs free energy for the uncatalyzed reaction. b. Use the physiological concentrations for glucose (2.0 mm) and inorganic phosphate (20 mM) to determine...
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