Question

Find the Norton equivalent circuit as seen from terminals a and b for the circuit shown in Figure 1.

Norton resistance (Ra-b) Blank 1, kiloohms

Norton current (Ia-b) Blank 2, mA

a 3kQ 10k 2 + 70V 250 0.01V. Y >5kQ Figure 3

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Answer #1

V = 49.63 v V = 1:48 V = Voc RN = Voc =12 = 1.48 v Isc Isc 0.50mA = 2.95kr o a ERN = 2.95 kn ISC b =0.50l mA

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