Question

- 1. For the MOSFET amplifier, given Vpp = 5V, -VSS=-5V, Rsig = 1Kohm, =K',(W/L)= 0.8 mA/V2, Ven= 1.1V, 1 = 0, Q point (0.5mA, 5V). a. Draw small signal equivalent circuit b. To get the Q point, determine values of Rp. and RG c. Find input impedance Rin = _ and output impedance Rout=__ d. Determine the g11 = and g22 for the amplifier e. Find the voltage gain Av=vo/Vsig=_ --

Answer 1

All the capacitor are open ckt - eat is Dc Analysis ! - look like OVDD g-point In 205mA , VDs=5v but value Io = 1/2 kn (wel vas van) ² 0.5mA = 2x0.8 (Vas 1:12 1 = (vas -1, 1)x018 Vas-H.1=1:12 Vas= 2:22] - KVL at input side! o-vas-Ip Rg tuss=0 Is Rg = 5-2.22 0.5 Rs = 2.78 Rs 5.56k 2 KVL at output side' n NDD - In Rp - Vps - In Rs + ss = 0 5-05 Rp - 5 - 2.78 +5=0 0.5Rp = 2.22 Scanned with Ro=4.44kh CamScanner Ang

@ Small signal equivalent:- Short the capacitor & DC voltage is ground- Rsign - © m = kn (he) (Yus="th) MAIN -0.86222-11) = 0.8X1.12 m gm. = 0.896 mA/V ou 115.56 = 112/15:56 Rin= Zin = 1 m ll Rs i Rin = 0°93% IS AN Rin= 0.9 kr Rout= Roll R3 =4.441110= 3.074k2 No = - gmrgs (Roll Rz) - 0 Vgg = Vg Vs [vg=0 Vgs = -1s = Vi CS Scanne sign a tvs = -vgs - CamScanner

Aga = g croll Rs) Av = 0.8.96X 3.074 Ao=2.755 CS Scanned with CamScanner