Question

QUESTION 10 Given the data below for the reaction, 2 A + 2 B + 4 C-> D + E + 3 F the reaction is order in A, order in B order in C and order overall. USE WORDS TO FILL IN THE BLANKS NOT NUMBERS(i.e., zero, first, second etc) Initial conc of A, ial conc of B, mol/L For Blank 3 Initial conc of C, Initial rate, mol/L.s 0.2 0.3 0.4 mol/L 0.2 0.2 0.4 0.6 mol/L 0.4 0.4 0.4 0.2 2 x 10-3 8 x 10-3 3.6 x 10 9.6 x 102

Answer 1

Ans :

When the concentrations of B and C are kept constant and that of A is doubled , the rate of reaction becomes four times , so the order of reaction is 2 with respect to A.

Now when the concentrations of A is made 1.5 times and that of B is doubled with C concentration constant , then the rate of reaction has become 4.5 times , so the rate of reaction is 1 with respect to B.

Now when the concentration of C is halved , and that of A is doubled and that of B is tripled , the rate of reaction becomes 12 times. So the order of reaction with respect to C will be 0.

overall order = 2 + 1 + 0 = 3

So here :

The reaction is second order in A , first order in B , and zero order in C , and third order overall.