Question

A manufacturer claims that the calling range (in feet) of its 900-MHz cordless telephone is greater than that of its leading competitor. A sample of 18 phones from the manufacturer had a mean range of 1120 feet with a standard deviation of 20 feet. A sample of 13 similar phones from its competitor had a mean range of 1110 feet with a standard deviation of 25 feet. Do the results support the manufacturer's claim? Let u be the true mean range of the manufacturer's cordless telephone and uz be the true mean range of the competitor's cordless telephone. Use a significance level of a = 0.1 for the test. Assume that the population variances are equal and that the two populations are normally distributed. Step 1 of 4: State the null and alternative hypotheses for the test. Answer 2 Points Keypad HO:M1 M2 HOM - M2

Answer 1

Solution Amanufacturer claims that the Calling range of its qooo :- Bazavied information is gilter by D=18 no=13 Ti = 1100 72= 1110 Giado G-05 - and QC01 sing Calculate i Stop Lof 4 :-Gat the null and altınolike hypothesis for this text: We have to the Gate the null and alternative hypothesis by co gis data is here, Nuu hypothesif it, Ho lu = 12 ) 24Herndike hypothesis is THA: 44>213) Clep pofu) - compute the Kalce of tou Claristic's le halk to obtained the value of ained the value of test eats test Gatistic by using by using giver dota is Elere HeGGatalic its {z - K G

heice 2 011)()+001) 6.7 [n11600) (18-1) 62-1) (05) [18+(3-0) - (11x cidd]+[194605) CUI-D) 6800 + 4500 (C1000 709 Cpc (296.2004 Spor Caegeldom) Esp -92.2057 Fors En ②, we get C1100-1110] +39.059 *fte uts VIB 10 9.20.59% 10.1624+8) LO Toe Boga ko.666976 ) 10__ 8.08241 ke 1.2043 - there fore, test Statiltic its 71.0373)

(Step 604 4: Bekimine the decling raceas We have to oblained t-critical Vale and drilion rule is, here, -)-t-eritical value tous droito-01 -t1o.1, df = 18-412--0) strol, df = 61-2) Etco.l, df=84) = 1.61145 - coe hake to compared the clothond t-Carihi Cal Valce is ttest <t-critica 1.2373 E 1.8114 fail to reject nalt bypothesis at &co.10 Therefore, >teritical Kabel = (1.611C Donal-creject Ho At 220.lo. Step Hofui Glate the conclusione conclusion at & co. 1o is We have to obtained the (fere, + test of Eritcal 19373 Kterites, Dorsot reject numi hypothesis of x=0.10 Therefore, otion ② is Comest fail to Reject wall hypothesis Optin