Question

P5. The load impedance Zį for the circuit below is adjusted until maximum average power is delivered to ZL. Let the phasor voltage Vs = 25 20° Vrms. a) Find Z b) Find the maximum average power delivered to Z 2522 i 1092 122 100Z0° Vrms (+) ZL

Please include all the steps used in the solution. Thank you!

Answer 1

al finding voca : vt 1.4 VTM 01018 250 - JION $17 3. Not enth Apple, men Analyn, - +25+10) 1, 451-0-0 -514 + T + $3 (14)-0 - 0 TH10+) T 108 60+ ) = 1000 016219-43 ) =100 11. 106 31-62 (12.45 3.16L-19-43 -I, + 12 + 1) = 0 til) Iz: SIM (3.1691-56) 125+(3:16-19.43°? 7 I 5431619-45 316.21.56² 51-19-42-71-56 = 5496A Vth = (33) IZ +(300) (20) Tym = 15Le v finding lica they lion T loole HM - 250 slon 1000 1 Scared with CamScanner

Apply mesh Analym -10018 + 5+310) It sty=0 +0 SI + Ijc zo ☺ I c = 4) + ® 7@ On (301, +j10 L) = 10018 (31.62(19.41) I10 let - = 3:16-18.430 dubstitute o in ® a lica SI 1513166–18-4309 CS Scanned with FC = 15.86-18.499 A) CamScanne

Zth Voce 15.161941 4th = 0.949 1941 2th 0.9 +0.14 ZL=true for maximum power transfer, + (0.949 1841")* T: 0.9491-19.45 ) ZL= (0.9 +30-3) 1ZL 20.940-3 .: T = Z= 0.949 -3.41 0.9-30-3 1. b) Amanz Ath=0.90-3 Vth 18 72=0.930-3 I VTE 0.9+0-3+ 0.9 10.3 z ing T-8 I > 8-13L0 "- mau & I x RL = 8.337* 0.9 = 62.5 waty Pmax = 62.5 waty Scanned With CamScanner