a) the electric potential difference:
v=E.(x1-x2)= -1.9*3.9 = - 7.41kV
b)the change of electric potential energy:
ΔE =q.Δv = 2.6x10^-6* -7410 = -19.26 mJ
c)conservation of energy => the kinetic energy:
ΔK= -ΔE = 19.26 mJ
d)V(x) = -1.9*x kV
Your last submission is used for your score points Tiplerb 23 P02 A uniform electric field...
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