Question

(4%) Problem 13: Using special techniques called string harmonics (or "flageolet tones"), stringed instruments can produce the first few overtones of the harmonic series. While a violinist is playing some of these harmonics for us, we take a picture of the vibrating string (see figures). Using an oscilliscope, we find the violinist plays a note with frequency f=815 Hz in figure (a). Otheexpertta.com A 14% Part (a) How many nodes does the standing wave in figure (a) have? 14% Part (b) How many antinodes A 14% Part (c) The string length of a violin is about L = 33 cm. What is the wavelength of the standing wave in figure (a) in meters? A 14% Part (d) The fundamental frequency is the lowest frequency that a string can vibrate at (see figure (b)). What is the fundamental frequency for our violin in Hz? 14% Part (e) In terms of the fundamental frequency f, what is the frequency of the note the violinist is playing in figure (c)? Grade = 100% Feedback Correct! Correct Answer Student Final Submission fe=2f fe=2f Grade Summary Deduction for Final Submission Deductions for Incorrect Submissions, Hints and Feedback [?] Student Grade = 100 -0 -0 = 100% Submission History All Date times are displayed in Central Standard Time Red submission date times indicate late work. Date Time Answer Hints 1 Oct 06, 2019 :19 PM fe=2f Feedback 14% Part (f) Write a general expression for the frequency of any note the violinist can play in this manner, in terms of the fundamental frequency f, and the number of antinodes on the standing wave A. A 14% Part (g) What is the frequency, in hertz, of the note the violinist is playing in figure (d)?

Answer 1

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Date సం S15 H2 and :- So, ftt 4 815 4- - 203.15H2 Sor the fundmental freuny is 203-25 H2 msusens Paut Ca) Part Cb)-4 Part Cc Part ( - 5 O165 m 203.75 H2