For the combustion of methane(CH4)
CH4 (g) + 2 O2 (g) --> CO2 (g) + 2H2O (g) Δ H = -882 kJ/mol
If 250.0 g of CH4 is burned , what is the energy change? ( Answers in scientific notation are entered such as 1.234 e4 )
Number of moles CH4 in 250g = amount of the methane/mw of methane= 250g/16.04 g/mole= 15.586 moles
According to the above balanced equation
1 mole of methane combustion produces 882 kJ of heat
Therefore combustion of 15.586 moles of methane will produce = 15.586 X 882 kJ of heat = 1.375 e4 kJ of heat
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