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sample observations = (75,82,77,83,79,85,80,87,81,102)
![solution Ik R --Ysamble value renes of ith = 88.1 Ane observation] XN NGM, 8=.5.49 27 95% confidence interoval of M. is give](http://img.homeworklib.com/questions/016ddc80-adb2-11ea-960f-2d2ac665a354.png?x-oss-process=image/resize,w_560)
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Questions A random sample of 10 Casio fx-991EX calculators being sold over the Internet had the...
1) In a random sample of eight cell phones, the mean full retail price was $526.50...
1) In a random sample of eight cell phones, the mean full retail price was $526.50 and the standard deviation was $184.00. Construct a 95% confidence interval for the true population price. Assume the sample was random and that the population of cell phone prices is normally distributed. Round your final answer to the nearest cent (2 numbers after the decimal)
hi there, having trouble with stats homework In a random sample of 22 people, the mean...
hi there, having trouble with stats homework
In a random sample of 22 people, the mean commute time to work was 31.5 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval fo the population mean u. What is the margin of error of u? Interpret the results. The confidence interval for the population mean u is ( 29.4, 33.6) (Round to one decimal place as...
In a random sample of 17 people, the mean commute time to work was 30.7 minutes and the standard deviation was 7.3 minutes
In a random sample of 17 people, the mean commute time to work was 30.7 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 95% confidence interval for the population mean μ. What is the margin of error of μ? Interpret the results. The confidence interval for the population mean μ is _______ . The margin of error of μ is _______ .Interpret the results A. With 96% confidence, it can...
In a random sample of six mobile devices, the mean repair cost was $70.00 and the...
In a random sample of six mobile devices, the mean repair cost was $70.00 and the standard deviation was $11.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval forte population mean. Interpret the results. The 95% confidence interval for the population m ean μ is (DO). Round to two decimal places as needed.) The margin of error is s (Round to two decimal places as needed.)...
1 2 3 10 11 12 13 14 15 16 21 20 Question 13 of 25...
1 2 3 10 11 12 13 14 15 16 21 20 Question 13 of 25 pointsAenet101 View question in a popup thn Remaining 8.1 Section Erre 47 dlo How smart is your phone? A random sample of 8 Samsung Galaxy smartphones being sold over the Internet in 2013 had the following prices, in dollars: 109 169 385 329 269 149 135 249 Sen dute Assume the population standard deviation is =81. Perform the following Part 1 of 3 (a)...
In a random sample of eight cell phones, the mean full retail price was $460.00 and...
In a random sample of eight cell phones, the mean full retail price was $460.00 and the standard deviation was $173.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean u. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 95% confidence interval for the population mean. (Round to one decimal place as needed.) Interpret...
In a current study, a random sample of 10 teachers from Utah and an independent random...
In a current study, a random sample of 10 teachers from Utah and an independent random sample of 10 teachers from Oregon have been asked to report their annual income. The data obtained are as follows: Annual income in dollars Utah 27546, 44083, 28883, 51011,47816, 37664, 29782, 38427, 34392, 46246 Oregon 43533, 23624, 40005, 53129, 29843, 26674, 40323, 33644, 39229, 39894 The population standard deviations for the annual incomes of teachers in Utah and in Oregon are estimated as $6400...
Can Anyone help me with these 7 questions? Questions: Q1. A random sample has been taken...
Can
Anyone help me with these 7 questions?
Questions: Q1. A random sample has been taken from a normal distribution and the following confidence intervals constructed using the same data: (38.02, 61.98) and (39.95, 60.05) (a) What is the value of the sample mean? (b) One of these intervals is a 95% CI and the other is a 90% CI. Which one is the 95% CI? Why? Q2. A civil engineer is analyzing the compressive strength of concrete. Compressive strength...
question 1. A random sample of 1002 adults in a certain large country was asked "...
question 1. A random sample of 1002 adults in a certain large country was asked " do you pretty much think televisions are necessity or a luxury you could do without?" Of the 1002 adults surveyed, 511 indicated that televisions are a luxury they could do without. Complete parts (a) through (e) below question 2. A researcher wishes to estimate the proportion of adults who have high-speed Internet access. What size sample should be obtained if she wishes the estimate...
answer all questions and ill leave a like :) part 1 a) find the sample mean...
answer all questions and ill leave a like :)
part 1
a) find the sample mean
b) find the sample standard deviation
c) construct a 99% confidence interval for the population mean
u
part 2
just answer the second part
part 3
just answer the second part
part 4
part 5
part 6
find answers a-c
8 of 10 (0 complete) HW Score: 0%, 0 of 10 pts Score: 0 of 1 pt 6.2.26-T Question Help The grade point averages...
hi there, having trouble with stats homework
In a random sample of 22 people, the mean commute time to work was 31.5 minutes and the standard deviation was 7.3 minutes. Assume the population is normally distributed and use a t-distribution to construct a 80% confidence interval fo the population mean u. What is the margin of error of u? Interpret the results. The confidence interval for the population mean u is ( 29.4, 33.6) (Round to one decimal place as...
In a random sample of six mobile devices, the mean repair cost was $70.00 and the standard deviation was $11.00. Assume the population is normally distributed and use a t-distribution to find the margin of error and construct a 95% confidence interval forte population mean. Interpret the results. The 95% confidence interval for the population m ean μ is (DO). Round to two decimal places as needed.) The margin of error is s (Round to two decimal places as needed.)...
1 2 3 10 11 12 13 14 15 16 21 20 Question 13 of 25 pointsAenet101 View question in a popup thn Remaining 8.1 Section Erre 47 dlo How smart is your phone? A random sample of 8 Samsung Galaxy smartphones being sold over the Internet in 2013 had the following prices, in dollars: 109 169 385 329 269 149 135 249 Sen dute Assume the population standard deviation is =81. Perform the following Part 1 of 3 (a)...
In a random sample of eight cell phones, the mean full retail price was $460.00 and the standard deviation was $173.00. Assume the population is normally distributed and use the t-distribution to find the margin of error and construct a 95% confidence interval for the population mean u. Interpret the results. Identify the margin of error. (Round to one decimal place as needed.) Construct a 95% confidence interval for the population mean. (Round to one decimal place as needed.) Interpret...
In a current study, a random sample of 10 teachers from Utah and an independent random sample of 10 teachers from Oregon have been asked to report their annual income. The data obtained are as follows: Annual income in dollars Utah 27546, 44083, 28883, 51011,47816, 37664, 29782, 38427, 34392, 46246 Oregon 43533, 23624, 40005, 53129, 29843, 26674, 40323, 33644, 39229, 39894 The population standard deviations for the annual incomes of teachers in Utah and in Oregon are estimated as $6400...
Can
Anyone help me with these 7 questions?
Questions: Q1. A random sample has been taken from a normal distribution and the following confidence intervals constructed using the same data: (38.02, 61.98) and (39.95, 60.05) (a) What is the value of the sample mean? (b) One of these intervals is a 95% CI and the other is a 90% CI. Which one is the 95% CI? Why? Q2. A civil engineer is analyzing the compressive strength of concrete. Compressive strength...
answer all questions and ill leave a like :)
part 1
a) find the sample mean
b) find the sample standard deviation
c) construct a 99% confidence interval for the population mean
u
part 2
just answer the second part
part 3
just answer the second part
part 4
part 5
part 6
find answers a-c
8 of 10 (0 complete) HW Score: 0%, 0 of 10 pts Score: 0 of 1 pt 6.2.26-T Question Help The grade point averages...
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